Show that a regularizing operator $K : C_c(\Omega) \to \mathcal{D}'(\Omega)$ has kernel $k \in C^\infty(\Omega \times \Omega)$.

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I am reading Francois Treves' Introduction to pseudodifferential and Fourier integral operators, vol. I.

Let $\Omega \subseteq \mathbb{R}^n$ be open. On page 11, Treves defines what it means for a continuous linear map $K : C_c^\infty(\Omega) \to \mathcal{D}'(\Omega)$ to be regularizing. $K$ is called regularizing if and only if $K$ extends to a continuous linear map $\mathcal{E}'(\Omega) \to C^\infty(\Omega)$.

Then Treves states the following proposition.

If $K : C^\infty_c(\Omega) \to \mathcal{D}'(\Omega)$ is regularizing, then the associated Schwartz kernel $k \in \mathcal{D}'(\Omega \times \Omega)$ is in $C^\infty(\Omega \times \Omega)$.

I am trying to prove this, and here's what I have so far. It is enough to show that $k$ is $C^\infty(\Omega \times \Omega)$ on tensor products since they are dense in $\mathcal{D}(\Omega \times \Omega)$. So let $\varphi, \psi \in C_c^\infty(\Omega)$. Use the statement of the Schwartz Kernel Theorem, and the fact that $K\psi \in C^\infty (\Omega)$ (since $\psi \in \mathcal{E}'(\Omega))$, to get

$$\langle k, \varphi \otimes \psi \rangle = \langle K\psi , \varphi \rangle = \int_\Omega (K\psi)(x)\varphi(x)dx.$$

But what I really want is some smooth function $k(x,y)$ of two variables, integrated against $\varphi \otimes \psi$. That is, what I want is

$$\langle k, \varphi \otimes \psi \rangle = \int_\Omega \int_\Omega k(x,y)(\varphi \otimes \psi)(x,y)dxdy$$.

Unfortunately, I am stuck and can't move further with the calculation. Hints or solutions are greatly appreciated!

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This result can be found in the Hormander's book, The Analysis of Linear Partial Differential Operators I. More precisely, Theorem 5.2.6., page 132.