At what base is square root of 120 natural number

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I got this problem i need to solve: At what base b, where b>2 , (120)b equals x2, where x is in decimal number system? I need to find all bases b, and i need to see the process of finding answer, so i can do it myself.

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$(120)_b = b^2+2b$

$b^2+2b$ can never be a perfect square as $b^2+2b+1$ is (except for $b=0$).