Bayesian Nets and weird probability

Question

I have to solve the following problem:

Suppose we have a bayesian net in which we have the following variables: R, PA and PR

Let:

P(R) = 0.1, P(PA) = 0.5, P(PR|R, PA) = 0.6, P(PR|¬R, PA) = 0.4, P(PR|¬R, ¬PA) = 0.1 and P(PR|R, ¬PA) = 0.2

What is the probability of P(¬R, PR, ¬PA)?

I started with P(¬R) and P(¬PA), because I can compute them as follows:

P(¬R) = 1 - P(R) = 0.9 P(¬PA) = 1 - P(PA) = 0.5

Then I think I can compute P(PR|¬R) and use bayes rule, however:

P(PR|¬R, PA) = 0.4 $\Rightarrow$ P(PR|¬R) * P(PA) = 0.4 \Rightarrow P(PR|¬R) = 0.8

I also have P(PR|¬R, ¬PA) = 0.1 \Rightarrow P(PR|¬R) = 0.2

The same for P(PR|R)... I get different results, so I can't apply bayes rule. This means I am obviously doing something wrong, where is my mistake? How can I solve it?

Answer 1

$$\begin{align}\mathsf P(R) =&~ 0.1\\ \mathsf P(PA) =&~ 0.5\\ \mathsf P(PR\mid R, PA) =&~ 0.6\\ \mathsf P(PR\mid ¬R, PA) =&~ 0.4\\\mathsf P(PR\mid ¬R, ¬PA) =&~ 0.1\\ \mathsf P(PR\mid R, ¬PA) =&~ 0.2\end{align}$$

What is the probability of $\mathsf P(¬R, PR, ¬PA)$?

$$\begin{align}\mathsf P(\neg R, PR, \neg PA)=&~\mathsf P(PR\mid \neg PA,\neg R)~\mathsf P(\neg PA, \neg R) \\[1ex] =&~ 0.1~\mathsf P(\neg PA,\neg R) \end{align}$$

We appear to be missing some information.   I suspect that it is that $R$ and $PA$ are independent.   Does your net indicate this?