The size of an insect population $N(x,t)$ is governed by the partial differential equation:
$\frac {\partial N}{\partial t}=p(N) + \frac {\partial^2 N}{\partial x^2}$
for some function $p(N)$ .
For cases where $p(N) \equiv 0$ is it possible to find a travelling wave solution of the form $N(x-ct)$, for wave speed c, such that $N\rightarrow 0$ as $|x| \rightarrow \infty$
I'm not where to start with this one, but since it's only 2 marks (the previous question was 10) I might be overthinking it . However, I still need to find some maths I need to do. I'm assuming that $p(N) \equiv 0$ implies that:
$\frac {\partial N}{\partial t}= \frac {\partial^2 N}{\partial x^2}$
But I'm not sure what the form $N(x-ct)$ actually means... Do I differentiate $x-ct$ with respect to $t$ and $z$ (which is zero) or what?
Any help is much appreciated. Thanks
Plug $N=\phi(x-c\,t)$ into the equation to get the ODE $$ -c\,\phi'=\phi''. $$ Solve it and find, for each $c\in\mathbb{R}$ the traveling wave solution $$ N=A\,e^{-c(x-ct)}+B. $$ Depending on the sign of $c$ we have $\lim_{x\to+\infty}N=0$ or $\lim_{x\to-\infty}N=0$, but never $\lim_{|x|\to\infty}N=0$.