Showing $\phi(x) = x -2\sin(x)\frac{1}{2}e^x$ is iteration function for $4\sin(x)-e^x$

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If I were to find an interation function for

$$4\sin(x)-e^x$$

I would do something like:

$$e^x = 4\sin(x)\implies x = \ln 4\sin(x) \implies x_{n+1} = \ln 4\sin(x_n)$$

or something with $\arcsin$, but I don't know how to arrive at $$\phi(x) = x -2\sin(x)+\frac{1}{2}e^x$$

But if I try to revserse it:

$$x= x -2\sin(x)+\frac{1}{2}e^x \implies 2\sin(x) = \frac{1}{2}e^x \implies 4\sin(x) = e^x \implies 4\sin(x)-e^x = 0$$

Can I just add $x$ and subtract like this? How it helps me in the iteration process?