I noticed and found only first three cases:
We can write $1$ as difference of two composites that have one prime factor $$3^2-2^3=1$$
and as difference of two composites that have two prime factors $$3\cdot 5 - 7\cdot 2 = 1$$
and as difference of two composites that have three prime factors $$2^2 \cdot 3^2 \cdot 43-7 \cdot 13 \cdot 17=1$$
I believe that this holds for every $k \in \mathbb N$, that is, that for every $k \in \mathbb N$ there exist composites $a_k$ and $b_k$ that have exactly $k$ prime factors and are such that we have $a_k-b_k=1$.
Is my belief true? Is this known? What is known about all of this and similar problems? Can someone find solutions for some larger $k$´s?
There is a similar question here by Peter where he wants that all prime factors are different.
I had too many comments, so I will put it in a partial answer, referring to the special numbers in the OP's question as $(k, l)$ composituples:
Definition: If $$a_{1,k},a_{2,k} = a_{1,k}+1,\ldots a_{l,k} = a_{(l-1),k}+1$$ are $l$ successive composites that have exactly $k$ prime factors, they are known as $(k,l)$ compo-situples. The set of these is denoted as $(k,l)_C\ni a_{l,k}$. I have investigated the following kind of set for prime pairs $p_n$ and $p_{n+1}$ such that I want to find the largest value of $l$ for a given $k$. $$(k,l)_C = \big\{\{p_n + 1,\ldots, p_{n+1} - 1\} : \text{card}(k,l) = l\,\land\,\Omega(a_{l,k}) = k\big\}.$$ Thus far, the largest value of $l$ has been $7$ such that $$(2, 7)_C =\{212, 213, 214, 215, 216, 217, 218, 219\}$$ for $k = 2$. Whether or not these are the smallest elements, I do not know.
Questions in regards to composituples that I have found:
Oddly enough, I have not written a program to find these. I simply just went here to look at prime numbers, and then I went here to decompose the composites in between a given prime pair.
This is strictly a partial answer, or rather, a very long comment as opposed to an answer.