$16=2^4$ and $0.75=3/4=3\times 2^{-2}$. Therefore $16.75_{10}=10000.11_2.\;$ Or do you want to have IEEE floating point format (for single, double)?
The IEEE double is computed as: sign bit $= 0,\;$ exponent $4+1023,\;$ significand including high bit =$100001100000000\dots$. Omitting the leading significand bit and combining the parts give
$16=2^4$ and $0.75=3/4=3\times 2^{-2}$. Therefore $16.75_{10}=10000.11_2.\;$ Or do you want to have IEEE floating point format (for single, double)?
The IEEE double is computed as: sign bit $= 0,\;$ exponent $4+1023,\;$ significand including high bit =$100001100000000\dots$. Omitting the leading significand bit and combining the parts give
written in 4-bit blocks
or as hexadecimal