I'm using expectation in this problem
If the expected value of 1 roll is:
E(X) = (1 * 1/6) + (2 * 1/6) + (3 * 1/6) + (4 * 1/6) + (5 * 1/6) + (6 * 1/6)
= 1/6(1+2+3+4+5+6)
= 21/6
= 7/2
Then would the expected total of 4 rolls be:
7/2 * 4 = 14?
I'm using expectation in this problem
If the expected value of 1 roll is:
E(X) = (1 * 1/6) + (2 * 1/6) + (3 * 1/6) + (4 * 1/6) + (5 * 1/6) + (6 * 1/6)
= 1/6(1+2+3+4+5+6)
= 21/6
= 7/2
Then would the expected total of 4 rolls be:
7/2 * 4 = 14?
Yes that is the expected total. As pointed out in the comments, the expectation of a sum the sum of the expectations so you can just straight-up sum them.