A and B are 3x3 matrices. Show that $AB \neq 0$ if both matrices have a rank of 2.

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A and B are $3\times 3$ matrices. I want to show that $AB \neq 0$ if both matrices have rank 2.

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Hint: Use Sylvester's inequality \begin{align} \operatorname{Rank}(AB) \geq \operatorname{Rank}(A)+\operatorname{Rank}(B)-3 \end{align}