I came across this problem and can't seem to figure out the solution.
The options are
789
879
978
798
Suppose that there are $8A$ 25 cents; $6A$ 50 cents; $5A$ dollar. So you will have $$5A + 3A+ 2A=420.$$
Then $A=?$ and the total number of coins is evident.
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Suppose that there are $8A$ 25 cents; $6A$ 50 cents; $5A$ dollar. So you will have $$5A + 3A+ 2A=420.$$
Then $A=?$ and the total number of coins is evident.