Is there a close form for the Fourier transform of $F(x)=H(x)\text{sech} (x)$, $H=\mathbf 1_{\mathbb R_+}$ ? Or is it easy to determine the range of $\hat F$?
2026-04-23 19:18:06.1776971886
A close form for a Fourier transform
53 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in CALCULUS
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