Is there something like a "countable Zorn's lemma" which is equivalent to the axiom of countable choice?
2026-03-29 06:28:55.1774765735
A "countable Zorn's lemma"?
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Not exactly. But there is one equivalent to Dependent Choice, the big brother of countable choice, and the principle most mathematicians think of when they think of countable choice.
The proof of this ranges from almost trivial to simple to "there's a small trick to remember", depending on how you define Dependent Choice.
Note, however, that the statement is not exactly the Zorn's Lemma condition, but it's not far from it: it omits the assumption "every chain which is finite has an upper bound". That is due to the fact that this is a theorem of $\sf ZF$, so it can be omitted. But if we want to generalize the equivalence, we need to bring it back. Which leads us to the following,
Which can now be generalized to arbitrary cardinals.
These were proved by Wolk in the following paper