If a function $f(x)$ is defined on the real numbers and absolutely integrable, does it say anything about the $lim_{x\to\infty}xf(x)$ ?
2026-04-05 20:15:21.1775420121
A function's absoulute integrability and its limit's relationship
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This limit can exist, but if it does then it must be zero. Because if it weren't, then $|f(x)|\geq c/x$ for some $c>0$ and $$\int |f|\geq \int c/x=\infty.$$
It can also happen that this limit not exist, with limsup and/or liminf being infinite