Consider the biorthogonal matrix propriety $\to$ $A^T \cdot B=I$.
How do I prove that $A \cdot B^T=I$?
2026-04-17 21:56:59.1776463019
A generalization of orthogonal matrices
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I assume that $A$ and $B$ are square matrices. Since $XY=I$ iff $YX=I$, we have $$ A^TB=I\Rightarrow BA^T=I\Rightarrow AB^T=(BA^T)^T=I. $$