Let $G$ be a finite group. For any two elements $a,b \neq e\in G$ there exits an automorphism $\sigma$ such that $\sigma(a)=b$. Prove that $G$ is abelian.
Only thing that I could conclude about the problem is that all elements have the same order.
Let $G$ be a finite group. For any two elements $a,b \neq e\in G$ there exits an automorphism $\sigma$ such that $\sigma(a)=b$. Prove that $G$ is abelian.
Only thing that I could conclude about the problem is that all elements have the same order.
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