My answer for this question is...
S=<{e1,e2,e3,...e10},I} I(linguist)={e1,e2,e3,...e10} I(married)={e1, e2,... e7}
I meant that there are 10 people, and 7 people out of 10 are linguists.To do this, I wanted to prove that "less than 60% of linguists are married". And, I wanted to prove that " Qx(linguist(x)∧married(x)) " is true.
(A) For the domain $S$ with 10 elements, we can use:
In this way, we have that 2 on 3 linguists are married: $\dfrac 2 3 = 0.66$ and 66% > 60%.
Thus, (1a) is false.
At the same time, we have that only 2 elements of the domain $S$ are both linguists and married: $\dfrac 2 {10} = 0.2$ and 20% < 60%.
Thus, (1b) is true, because less than 60% of the elements of the domain $S$ are linguists and married.
(B) Now we want that (2a): "Less than 60% of the linguists are married" comes out true.
This is quite straightforward: it is enough to choose sets $I(linguist)$ and $I(married)$ in the ratio $2 : 1$.
But we want also that (2b): "$Qx \ (\text {linguist} (x) \to \text {married} (x))$ is false.
This means that we want that at least 60% of the entities in $S$ make the formula $\text {linguist} (x) \to \text {married} (x)$ true.
In conclusion, we can set: $I(linguist) = \{ e_1,e_2 \}$ and $I(married) = \{ e_1 \}$.
We have that 1 on 2 linguist is married: $\dfrac 1 2 = 0.5$ and 50% < 60%. Thus, (2a) is true.
At the same time, for every $e_i, i=3,\ldots,10$ we have that $\text {linguist} (e_i) \to \text {married} (e_i)$ is true.
Thus, 80% of the total population of $S$ satisfy the formula $\text {linguist} (x) \to \text {married} (x)$, and his means that "$Qx \ (\text {linguist} (x) \to \text {married} (x))$ is false.