I've just begin a course on character theory. Juste to repeat we say :
Let $G$ be a finite group. Then a character $\chi$ is a morphism from $G \to \mathbb{C}^*$. We then have some property on dual group $G^{\wedge}$ :
For example with the inner product : $\langle \chi_1, \chi_2 \rangle = \frac{1}{\mid G \mid } \sum_{g \in G} \chi_1(g) \overline{\chi_2(g)}$ all the element of the dual group are orthogonal which means $\langle \chi_1, \chi_2 \rangle = 0, \chi_1 \ne \chi_2$
My problem is that I don't understand all these definitions which are a bit cumbersome for me.
Why are we defining the dual of group as all the morphism from $G$ to $\mathbb{C}^*$ and not from $G$ to an other group ?
In linear algebra I have a really good sens of what an inner product is, and what it represent (it's a projection between two vectors). Here I don't understand what geometrically this inner product represent. The factor $\frac{1}{\mid G \mid}$ in the formula maybe is there to say : we are kind of looking at the barycenter of the element of the dual ?
With some intuition is it then possible that : the orhtogonality of the element of the dual is an obvious fact ?
Thank you !
The fantastic thing about the dual group $G^\vee = \operatorname{Hom}(G, \mathbb{C}^\times)$ is that it is in fact a group, and so a lot of questions can be reduced to simply asking whether something is the identity or not. Here are some facts about linear characters:
After this we can prove the relation $$\sum_{g \in G} \chi(g) = \begin{cases} |G| & \text{if } \chi = \chi_{\mathrm{id}} \\ 0 & \text{otherwise} \end{cases}$$ the first case is clear, so let $\chi \neq \chi_{\mathrm{id}}$. Then there is some $g_0 \in G$ such that $\chi(g_0) \neq 1$, and we have $$\chi(g_0) \sum_{g \in G} \chi(g) = \sum_{g \in G} \chi(g_0 g) = \sum_{g \in G} \chi(g)$$ and hence $\sum_{g \in G} \chi(g) = 0$.
After this, the orthgonality relations are clear, since $\langle \chi_1, \chi_2 \rangle$ is just plugging in $\chi_1 \overline{\chi_2} = \chi_1 \chi_2^{-1}$ into that sum up above.
If you read further into the representation theory of finite groups, it will turn out that for any irreducible representation $V$ of $G$ (not just one-dimensional representations), there is a character $\chi_V$, and we have $\langle \chi_V, \chi_W \rangle = 1$ when $V$ and $W$ are isomorphic representations, and 0 when they are different. This is a good motivating example for defining the inner product.