Let $R$ be a non-commutative ring with $1$ and $a,b\in R$ such that $ab=1 \neq ba.$ Could anyone advise me on how to show there exists $c\in R-\{b\}$ such that $ac=1 \ ?$
Hints will suffice. Thank you.
Let $R$ be a non-commutative ring with $1$ and $a,b\in R$ such that $ab=1 \neq ba.$ Could anyone advise me on how to show there exists $c\in R-\{b\}$ such that $ac=1 \ ?$
Hints will suffice. Thank you.
Define a homomorphism of groups $R \rightarrow R$ which is multiplication by $a$ on the left, i.e. $x \mapsto ax$. Then $1$ and $ba$ have the same image.
Then you can conclude...