Let a stochastic process $(x(t),\theta(t))$ be given by $$ \dot{x}(t)=f(x(t),\theta(t)) $$
for a well defined continuous function $f(\cdot,\cdot)$. Let $\mathcal{F}_t$ denote the natural filtration of $(x(t),\theta(t))$ on the interval $[0,t]$. Then, is it implicit that the stochastic process $(x(t),\theta(t))$ is Markov with respect to $\mathcal{F}_t$? Or do we have prove it explicitly?
May be the question looks too stupid. But any help will be of great use.
If ever you must prove it, with no further hypothesis, then some trouble might arise... Assume for example that $x(0)=0$ and $\dot x(t)=\theta(t)$, then $x(t)=\int\limits_0^t\theta(s)\mathrm ds$ is not always Markov with respect to the filtration $(\mathcal F_t)$. Note that $\mathcal F_t=\sigma(\theta(s);0\leqslant s\leqslant t)$.