A question about $\pi$

Question

Is it correct?

$$\pi=3+\cfrac{\log(\frac{1}{\Delta})}{\log(\frac{1}{\Delta^{\sqrt{\Omega}}})},$$

with $$\Omega=\cfrac{1}{(\pi-3)^{2}}\thickapprox49.8790939?$$

Answer 1

For sure:

$$ 3+\frac{\log(\frac{1}{\Delta})}{\log(\frac{1}{\Delta^\sqrt{\Omega}})}=3+\frac{\log(\frac{1}{\Delta})}{\sqrt{\Omega}\log(\frac{1}{\Delta})}=3+\frac{1}{\sqrt{\Omega}}=3+\pi - 3 = \pi $$