Consider the following lines
- $x-y-1=0$
- $x+y-5=0$
- $y=4$
The line 1 is the axis of the parabola, the line 2 is the tangent at the vertex to the same parabola, and the line 3 is another tangent to the same parabola at some point $P$.
Now let a circle $C$ circumscribing the triangle formed by tangent and normal at the point $P$ and the axis of the parabola.
Then how can I find the equation of the circle?
I have tried and found that the vertex of this parabola is (3,2). Need help....don't know how to proceed further.... Thanks in advance...
The problem does NOT ask you to find the equation of the parabola nor does this problem really have anything to do with a parabola, strictly speaking. The problem asks you to find the circle passing through the three points of intersection of the lines y= x+ 1, y= 5- x, and y= 4.
What are those three points? How do you find the equation of a circle passing through those points,