A Rational Problem about a Pilot and His Plane

Question

Here's a problem that I can't seem to solve. It was discussed to us last week, but I had a fever so I wasn't able to understand the answer and solution.

Due to inclement weather, the pilot of a plane slows down the plane’s regular flying rate by $25. This results to an additional $1.5$ hours in covering the 3,000-km distance to its regular time required for the trip. Find the regular rate of the trip.

Answer 1

The pilot is moving at $\frac {3v}{4}$ of its normal speed and it took the regular time $t+1.5hrs$ to arrive. Perhaps you can use the formula $vt=d$ and apply it here?

Answer 2

Let regular rate be S.

Then reduced rate during trip = .75S

Time to cover 3,000 km at regular rate = $\frac{3000}{S}$

Time to cover 3,000 km at reduced rate = $\frac{3000}{.75S}$

Difference in time 1.5 hours.

$\frac{3000}{.75S} - \frac{3000}{S} = 1.5$

Solve it to find S that is the required answer.