Suppose that we have $m$ vectors in $\mathbb{R}^n,$ $v_1,v_2,...,v_m$, such that
$X^Tv_i=0,~\forall i.$
Prove that if $\dim(\langle v_1,...,v_m\rangle)=l$ then the answers of above equation ($X$) is $n−l$ dimension.
Can anyone prove this with Rank-nullity theorem?
You are looking for the $\dim (\text{nul}(V))$ with $V = (v_1,\ldots,v_m)$