Consider the following sequence where $ x_{1}=2018$, $x_{2}=1$ and $$x_{n+1}=2018x_n +2019x_{n-1}$$ for $n\ge 2$ Show that there must exist a term in the sequence divisible by $2018^ {2018}$
2026-03-25 03:24:21.1774409061
A sequence+ divisibility proof contest math
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