Given $f(x)=log(1+x^2)-log(1+(x-\delta_1)^2)$ and $g(x)=log(1+x^2)-log(1+(x-\delta_2)^2)$ ,is there any way to calculate $\frac{df(x)}{dg(x)}$ taking $\delta_1$ and $\delta_2$ as fixed numbers?
2026-03-26 11:16:47.1774523807
A special case of implicit differentiation
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Maybe $$\frac{df}{dg}=\frac{\frac{df}{dx}}{\frac{dg}{dx}}$$ ?