A subgroup of direct product of countable copies $\mathbb{Z}$

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This is an example from Rotman's Homological Algebra (p.122, old edition).

Let $G$ be the direct product of countable copies of $\mathbb{Z}$ (say, group of sequences of integers).

Fix a prime $p$.

Let $S$ be the subgroup consisting of all those sequences in $G$ such that for every $k\ge 1$, all except finitely many entries of sequence are divisible by $p^k$.

It is then shown in book that this subgroup is not free (by some arguments).

It was shown that this subgroup is uncountable; I didn't understand this fact about cardinality. Any hint for this?