I calculated the cube integral over $[0,1] \times [0,1] \times [0,1]$.
The solution is quite close to $\frac{\pi}{2}$. is it just a coincidence? is there an intuition for why it is?
I calculated the cube integral over $[0,1] \times [0,1] \times [0,1]$.
The solution is quite close to $\frac{\pi}{2}$. is it just a coincidence? is there an intuition for why it is?
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