A very interesting problem.

Question

Complete the following table of mathematical operations, $$\begin{align*}2+2+2&=6\\ 3 \ \quad 3\ \quad 3&=6 \\ 4 \ \quad 4\ \quad 4&=6 \\ 5 \ \quad 5\ \quad 5&=6 \\ 6 \ \quad 6 \ \quad 6&=6 \\ 7 \ \quad 7\ \quad 7&=6 \\ 8 \ \quad 8\ \quad 8&=6 \\ 9 \ \quad 9\ \quad 9&=6\end{align*} $$

I know that in the second there is a $ \cdot $ and then a $ - $, and it is true that $ 3 \cdot 3-3 = 6 $, but in the others I do not know another complex mathematical operation that helps me complete that table, someone help me.

Answer 1

$$\begin{align*}2+2+2&=6\\ \sqrt 3 \cdot \sqrt 3\ +3&=6 \\ \sqrt4 +\sqrt 4\ +\sqrt 4&=6 \\ 5\div 5+ 5&=6 \\ 6 \cdot 6\div 6&=6 \\ -7\div{7}+7&=6 \\ \sqrt[3]8 +\sqrt[3]8 +\sqrt[3]8 &=6 \\ \sqrt 9 \cdot\sqrt 9\ -\sqrt 9&=6\end{align*} $$

Answer 2

$$ 2 + 2 + 2 = 6 $$

$$ 3 \times 3 - 3 = 6 $$

$$ \sqrt4 + \sqrt4 + \sqrt4 = 6 $$

$$ 5\div5 + 5 = 6 $$

$$ 6 + 6 - 6 = 6 $$

$$ 7 - 7\div7 = 6$$

$$ \sqrt[3]8 + \sqrt[3]8 + \sqrt[3]8 = 6$$

$$ 9 - 9 \div \sqrt9 = 6 $$