$AA^T$ rank and singularity

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Let $A\in M_{m,n}$ and $m>n$. Can rank of $AA^T$ cannot be greater than rank of $A$? And is $AA^T$ singular matrix?

I think both of these are correct, since I tried some examples, but I can't prove them.

EDIT:

I've figured out that ranks have to be the same since $ker(A)=ker(AA^T)$.