One meter of AB-needle has line having n = 5.7*10^-14 nucleons with mass m = 1.67*10^-27 kg. Total mass of one meter AB-needle equals only 10^-12 kg/m.
M1 = nm = 5.7*10^-14 ×1.67*10^-27 = 10^-12 kg/m.
One million kilometers of AB-needle weights only 10^-3 kg/Mm. For transferring the large force we can take the thin cable from AB-needles.
What does n stands for I'm really confused, how can you have a number lower than 1 to count the number of nucleons in a meter string of AB-matter. I thought you would count the number in a meter needle and times it by mass of each nucleons to arrive at mass of a length of needle?
It's very likely to be a typo (on both lines). It most likely meant $n=5.7(10^{14})$.
We see on the next line of calculation that this interpretation would make sense, given the result.
$$5.7(10^{14}) ×1.67(10^{-27}) = 10^{-12}$$