In one of my previous questions (which is now deleted), I used, without proof, the "wrong" fact that if $A\cong B$ and $C\cong D$, and if $C$ is normal in $A$ and $D$ is normal in $B$, $A/C\cong B/D$.
Someone commented that it is not even true for a finite group, and I am wondering what a counterexample might look like. Also, under what circumstances (if any) is the above assertion valid? If I assert that it is finite and abelian, is it enough?
Thanks bunch in advance!
Set $A=B=\mathbb{Z}$, $C=2\mathbb{Z}$, $D=3\mathbb{Z}$.
It's also not true for finite and abelian groups: take $A=B=\mathbb{Z}/4\mathbb{Z}\times \mathbb{Z}/2\mathbb{Z}$ and consider $C=2\mathbb{Z}/4\mathbb{Z} \times \{0\}$, $D=\{0\}\times \mathbb{Z}/2\mathbb{Z}$.