Question:
If $A$ and $B$ are measurable set,
$ m(A) + m(B) = m(A\cup B) + m(A\cap B)$
equality is provided.(Lebesgue Measure)
My Solution:
$m(B) = m(B\cap A) + m(B \cap A^\mathbb{c}) = m(B\cap A) + m(B \setminus A)$
$m(A \cup B ) = m((A \cup B) \cap A) + m((A \cup B) \cap A^\mathbb{c}) = m(A) + m(B \setminus A)$
So, Would it be equal?
$m((A \cup B) \cap A^\mathbb{c}) = m(B \setminus A)$
If it's equal
$ m(B \setminus A) = m(A \cup B ) - m(A)$
$ m(B \setminus A) = m(B ) - m(A \cap B)$
hence,
$ m(A) + m(B) = m(A\cup B) + m(A\cap B)$
$$(A \cup B) \cap A^C=(A\cap A^C)\cup (B \cap A^C)=\emptyset\cup (B\setminus A)=B\setminus A$$