is this correct
$ \left| |a| \exp(-i c)-|b| \exp(-i d) \right|^2=|a|^2-2|a||b|+|b|^2$
Thank you
$$\left| |a| \exp(-i c)-|b| \exp(-i d) \right|^2=(|a| \exp(-i c)-|b| \exp(-i d) )\times( |a| \exp(i c)-|b| \exp(i d))$$ so $$\left| |a| \exp(-i c)-|b| \exp(-i d) \right|^2=|a|^2-(\exp(i (c-d))+\exp(i (d-c))|a||b| +|b|^2$$ so $$\left| |a| \exp(-i c)-|b| \exp(-i d) \right|^2=|a|^2-2\cos(c-d)|a||b| +|b|^2$$
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$$\left| |a| \exp(-i c)-|b| \exp(-i d) \right|^2=(|a| \exp(-i c)-|b| \exp(-i d) )\times( |a| \exp(i c)-|b| \exp(i d))$$ so $$\left| |a| \exp(-i c)-|b| \exp(-i d) \right|^2=|a|^2-(\exp(i (c-d))+\exp(i (d-c))|a||b| +|b|^2$$ so $$\left| |a| \exp(-i c)-|b| \exp(-i d) \right|^2=|a|^2-2\cos(c-d)|a||b| +|b|^2$$