Adding imaginary number "i" raised to high exponents

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I'm answering an MCQ regarding the topic. Some of my answers to the questions doesn't match the answer key. (It has no solution only the final answer.) I just want to know whether I'm right or wrong or maybe the key to corrections is erroneous. Just a yes or no is suffice or a tip if its wrong.

1.) Simplify the expression $i^{1999} + i^{1999}$ where I is an imaginary number.

  • $i^{1996} \cdot i^3 + i^{1996} \cdot i^3$
  • $i^{1996}$ cancels out as it is equal to 1, so: $i^3 + i^{3} =$ -2i

However, the answer key states that the correct answer is 0.

2.) Evaluate $4i^{410} - i^{864} + i^{601} + i^{1203}$

  • $4(i^{408} \cdot i^{2}) - i^{864} + i^{600} \cdot i^1 + i^{1200} \cdot i^3$
  • Those with exponents divisible by 4 will be equal to 1, so : $4i^2 - 1 + i + i^3 = $ -5

But the answer key states that the correct answer should be 3.

3.) If $i^2 = -1$, then $i^7 - i^6 + i^5 = $ ?

  • $i^4 \cdot i^3 - i^4 \cdot i^2 + i^4 \cdot i^1$
  • $i^4$ is equal to 1 so: $i^3 - i^2 + i = $ 1

But the answer key states that it should be -i

So, is there something wrong on how I answer this kind of questions? Thank you in advance. :)

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I get

$i^{1999}=-i$, so $i^{1999}+i^{1999}=-2i$.

$4i^{410} - i^{864} + i^{601} + i^{1203} =-4-1+i-i=-5$.

$i^7-i^6+i^5=-i+1+i=1$.