If I add a matrix to its transpose matrix, will I get a symmetric matrix? Is $B := A + A^\top$ symmetric?
2026-03-25 07:38:59.1774424339
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Adding matrices to their transpose
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Yes (when $A$ is a square matrix of dimension $n\times n$).
Let $1\le i,j,k\le n$.
The diagonal elements of both $A$ and $A^T$ are the same ($\{a_{ii}\}$) so that of $A+A^T$ are $2\times\{a_{ii}\}$.
Also, a non-diagonal element of $A$ has the form $\{a_{jk}\}$ where $j\neq k$ and that of $A^T$ has the form $\{a_{kj}\}$. So the element of $A+A^T$ on the $j$th row and $k$th column is the same as that on the $k$th row and $j$th column - both are equal to $a_{jk}+a_{kj}=a_{kj}+a_{jk}$.
Combining these two yields the result.
Yes
$$B^T=(A+A^T)^T=A^T+(A^T)^T=A^T+A=A+A^T=B$$
Note $A$ and $A^T$ must have the same dimensions, hence $A$ must be square.