Ancient babylonian geometry

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An old Babylonian tablet calls for finding the area of an isosceles trapezoid whose sides are 30 units long and whose bases are 14 and 50.

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That Babylonian method is at least as easy to understand as the standard formula.

                          E___________  
                         /|          |\  
                        / |          | \  
                       /  |          |  \  
                      /   |          |   \  
                     /____|__________|____\  
                     A    B          C    D

The sketch above is not to scale, but it’s good enough to show the idea. You know that the distance $|AD|=50$, that $|BC|=14$, and that $|AB|=|CD|$, so you can calculate $|AB|$. You know that $\triangle ABE$ is a right triangle, and once you’ve calculated $|AB|$, you’ll know both $|AE|$ and $|AB|$ and will be able to use the Pythagorean theorem to calculate $|BE|$. With that information calculating the areas of the central rectangle and the two triangles is easy.