There is a clear relation between the eigenvectors of $A$ and $A^T$. They are mutually orthogonal.
But I cannot find a similar relation between the singular vectors of $A$ and $A^T$.
I am looking for an expression like $\cos$$($"angle between singular vectors of $A$ and $A^T$"$)=$...
One day later:
Referring to the articles of EngleField & Farr on eigencircles:
Englefield, M. J., & Farr, G. E. (2006). Eigencircles of 2 x 2 matrices. Mathematics Magazine, 79(4), 281 - 289
Englefield, M., & Farr, G. (2010). Eigencircles and associated surfaces. Mathematical Gazette, 94(531), 438 - 449
Let $A=$ $\begin{bmatrix} a & b \\ c & d \\ \end{bmatrix}$ $f=\frac{a+d} {2}$ , $g=\frac{b-c} {2}$ ,
$\theta= -atan2(g,f) = \text{the angle between the singular vectors of }A\text{ and }A^T$
Moreover: if A is decomposed using SVD :
$ A = U \Sigma V^T$
$ U \text{ contains the singular vectors of }A$.
$ V \text{ contains the singular vectors of }A^T$.
$ u_i= \frac{A v_i}{\sigma_i} \text{ connects the singular vectors of }A\text{ and }A^T$.
$\theta$ also equals $-angle \ of \ rotation \ UV^T$ or $+ angle \ of \ rotation \ VU^T$.