
A person has 3 cups with him , he has a 8L cup filled with coke , and an empty 5L and 3L cups, using these three can anyone make 2 cups each with 4L to be served to two people. This person has no measuring instruments and assume that things like coke doesn't spill or anything, and you should make a cup with 4L and another cup with 4L. I believe I did get the answer to this back then when I spent one whole day with my friends in school trying to solve this. But now I can't remember it , and it's for the others too I'm sharing this question.
This is a classic problem. I think Lloyd and Dudeney had similar (and much more difficult) problems in their puzzle books.
Note $L$ - cup with 8L of coke, $M$ - cup of 5L, $S$ - cup of 3L.
Pour $L\to S$, then $S\to M$. Pour $L\to S$, then $S\to M$ until $M$ fills up. Now you have 5L in $M$ and 1L in $S$. Pour $M\to L$, then $L\to S$, $S\to M$.
Now you have 4L of coke in $L$ and 4L of coke in $M$.