Given a matrix $A$, if the rank of $A$ is defined to be the highest order of non-vanishing minor of $A$.
If we apply the above definition, how to check that $\operatorname{rank}(AB) \leq \operatorname{rank}(A)$?
2026-04-07 05:06:25.1775538385
Another proof the $\operatorname{rank} (AB) \leq \operatorname{rank} (A)$
56 Views Asked by user63181 https://math.techqa.club/user/user63181/detail AtRelated Questions in LINEAR-ALGEBRA
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