I am looking for a smooth function $f_\sigma(x)$ with parameter $\sigma \in [0,1]$, such that
$$\lim_{\sigma \rightarrow 1}\ f_\sigma(x) = \cos(\pi x)$$
and
$$\lim_{\sigma \rightarrow 0}\ f_\sigma(x) = \sum_{i = -\infty}^{\infty}(-1)^i\ \delta(x-i) =: D(x)$$
i.e. a series of alternating delta peaks, superelevating the peaks of the cosine.
The relation between cosine and Dirac's delta function $\delta$ was given by Fourier:
$$\delta(x) = \frac{1}{2\pi}\int_{-\infty}^{\infty}\ dp\ \cos(px)$$
You can also consider $\delta$ as the limit
$$\delta(x) = \lim_{\sigma \rightarrow 0} \frac{1}{\sqrt{2\pi}\sigma} e^{-x^2/2\sigma^2}$$
Given this definition of $\delta$ there is a straight-forward and somehow "trivial" solution:
$$f_\sigma(x) = \sigma\cos(\pi x) + (1-\sigma)\sum_{i = -\infty}^{\infty}(-1)^i\ \frac{1}{\sqrt{2\pi}\sigma} e^{-(x-i)^2/2\sigma^2}$$
Question 1: Is there a more "simple", "natural" family of functions $f_\sigma(x)$, esp. without infinite sums?
Question 2: What is the Fourier transform of $D(x)$?

Take $\varphi(x) = e^{-\pi x^2}$ or any function you like
Let $$\psi_\alpha(x) = \frac{1}{\alpha }\sum_n (-1)^n \varphi( (x- n)/\alpha)$$ $$F_\alpha(x) = (1-\alpha)\psi_\alpha(x) +\alpha \cos(\pi x), \qquad\qquad f_\sigma = F_{\displaystyle e^{-\sigma}}$$