I need help, I need to answer this problem
I tried $\left [ ln\tfrac{1-sinx}{1+sinx}\right ]^{3}$ plug in to $\frac{2\cos x}{1-\sin ^{2}x}dx$
but i think it's quite incorrect and I'm missing something, can someone told me the correct first step on answering or re writing this problem,? I'm struggling to start and continue this one,
Thank you in advance...
Hint:
$$D\bigg(\ln(\frac{1-\sin x}{1+\sin x})\bigg)=\frac{-2}{\cos x}$$