Let $X,Y$ be Banach spaces and let $A:X\rightarrow Y,B:Y^*\rightarrow X^*$ be linear maps.
Show that if for all $x\in X,y\in Y^*,y^*(Ax)=By^*(x)$, then both $A$ and $B$ are continuous
Let $X,Y$ be Banach spaces and let $A:X\rightarrow Y,B:Y^*\rightarrow X^*$ be linear maps.
Show that if for all $x\in X,y\in Y^*,y^*(Ax)=By^*(x)$, then both $A$ and $B$ are continuous
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Noting that for a fixed $x$ and $\|y^*\| \le 1$, the map $y^* \mapsto y^*(Ax)$ is bounded uniformly by $\|Ax\|$.
Then Banach Steinhaus gives $\sup_{\|x\| \le 1, \|y^* \| \le 1} |y^*(Ax)| < \infty$.
We have $\|B\| = \sup_{\|y^*\| \le 1} \|B y^*\| = \sup_{\|x\| \le 1, \|y^*\| \le 1} |B y^*(x)| = \sup_{\|x\| \le 1, \|y^*\| \le 1} |y^*(Ax)| $, hence we see that $B$ is bounded.
The other direction follows directly from this bound.