Am I correct to conclude that:
all integers with exponent over 52 in the 64 bit floating point will be even? For example, if exponent is
53, and the mantissa is0000000000000000000000000000000000000000000000000001, then the number is100000000000000000000000000000000000000000000000000010- ends in10. If the mantissa is54the number ends with100.the more we increase the exponent, the more integer numbers can not be represented - for the exponent of
54- it's impossible to represent one number -9007199254740993, with exponent of55- we can't represent3numbers (because we have two bits left out of mantissa which can have combinations of 01,10,11).