From what I understood, cardinal numbers are defined as:
$\aleph_0$ = the cardinality of $\mathbb{N}$
$\aleph_{n+1}$ = is the least cardinal number greater than $\aleph_n$
The continuum hypothesis states that the cardinality of $\mathbb{R}$ is $\aleph_1$. I more or less understand this cannot be proven (does not follow from ZFC).
However, can it be proven dat there in fact is a 'least cardinal number' greater than $\aleph_0$?
Is it possible that there are sets with cardinality $\aleph_{1/2}$, $\aleph_{1/3}$, et cetera, so to speak?
Or expressed differently: is it possible that for every set A with cardinality CA > $\aleph_0$, there exists another set B with cardinality CB where CA > CB > $\aleph_0$?
Cardinal numbers are special ordinal numbers, and the class of ordinals is well-ordered. So it does make sense to talk about the first ordinal that is not in a bijective correspondence with $\omega$, this is a unique and well-defined ordinal number and is defined to be $\aleph_1$. By definition all smaller ordinals are countable, so there is no intermediate cardinality between $\aleph_0$ and $\aleph_1$. The same goes for $\aleph_\alpha$ and $\aleph_{\alpha+1}$, mutatis mutandis.