Are eigenvectors a basis set for any invariant subspace?

Question

Let $A\in \mathbb{R}^{n\times n}$ (i.e., a real square matrix). Assume that $v_1,\dots, v_m$ ($m\le n$) are eigenvectors of $A$.

Can any $d-$dimensional invariant subspace of $A$ be constructed using $d$ numbers of $v_i$'s?