Are there infinitely many numbers $X$ so that both $X+1$ and $\frac{X}{2}+1$ are squares?

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My grandad gave me a challenge and, like any non-cheating child, I wrote a program to solve it for me

It goes like this: $48$ is a peculiar number, because

  • $48+1$ is square, and
  • $\frac{48}{2}+1$ is square.

Find the next $3$ smallest examples of numbers $X$ that follow both of those rules.

  • $X+1$ is square
  • $\frac{X}{2}+1$ is square.

I wrote some code and ran it and got quite a few large examples, even so high as $16$ digits.

But then, after a while, I stopped finding new numbers. It is likely that my computer/my coding skills just can't take it high enough in a small time frame, but my math brain is itching.

Will this stop or will this pattern go on forever.

Why?

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Let $x=2n$. Then we are told that $n=m^2-1$ and $2n=M^2-1$ for suitable natural numbers $m,M$. It follows that $$2m^2-2=M^2-1\implies 2m^2=M^2+1$$ or $$\boxed { M^2-2m^2=-1}$$

This is one instance of the classical Pell's Equation. And the solution is well documented online.