Let $\alpha$ be an ordinal. We say that $\alpha$ is good iff for every $\beta\in \alpha$, there exists $\gamma\in \alpha$ such that $|\scr{P}(\beta)|\leq |\gamma|$.
Question: Is the set of natural numbers the only good ordinal ?
Thank you
Let $\alpha$ be an ordinal. We say that $\alpha$ is good iff for every $\beta\in \alpha$, there exists $\gamma\in \alpha$ such that $|\scr{P}(\beta)|\leq |\gamma|$.
Question: Is the set of natural numbers the only good ordinal ?
Thank you
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No, the empty set also satisfies this, as do any strong limit cardinal.
Note that this condition says that $\lambda<\kappa\implies2^\lambda<\kappa$.
It is easy to show there is a proper class of strong limit cardinals, and if you are familiar with $\beth$ numbers, then the limit $\beth$'s are strong limit cardinals.