I'm slightly confused about the following question:
Find the area between $y^2 = x$ and the line $x = 4$. So I've done other area questions but they have been presented a bit differently to this.
My first instinct is to find $y$. i.e. $y = \sqrt{x} = x^{\frac{1}{2}}$, and my limits of integration then are a = 0 and b = 4. So altogether I want $\int_{0}^{4} x^{\frac{1}{2}} dx$. Is that all there is to it?
Because if I sketch $y^2 = x$, it is not the same graph as $y = \sqrt{x}$ (I understand that we are in the real 2-dimensional plane, not imaginary), but this is throwing me a bit wondering if I'm doing it right.
HINT
Note that we can write
$$\int dA=2\int_0^4 \sqrt x\, dx$$
or as an alternative
$$\int dA=16-\int_{-2}^2 y^2 dy$$