Find the area of the region enclosed by the parabola $y=x^2-3x$, the line $y=2x$, and the line $y=x$.
This time, I could not break up the area into more parts, so I did not know how to calculate the area. Does anyone know how to do this?
Find the area of the region enclosed by the parabola $y=x^2-3x$, the line $y=2x$, and the line $y=x$.
This time, I could not break up the area into more parts, so I did not know how to calculate the area. Does anyone know how to do this?
Hint:
\begin{align*} \text{Area}&=\int_0^4\left(2x-x\right)dx+\int_4^5\left[2x-\left(x^2-3x\right)\right]dx \end{align*}