Area enclosed by polar curves explination

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I have frequently used the formula $A=\int_{\theta_1}^{\theta_2} \frac {r^2} {2} d\theta$ when dealing with polar curves, however I never really understood where this formula came from. I'd very much appreciate it if someone would explain it to me in depth.

Thank you all for your time.

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Let me try to give you some intuition to the formula.

First consider the case where $r$ is constant, $\theta_1 = 0$ and $\theta_2 = 2\pi$. Then the polar curve is a circle with radius $r$, and you can verify that indeed $A = \pi r^2$.

Now for each $n > 0$, divide the circle into $n$ equal sectors. The area of a circle equals the sum of the areas of these sectors. That is, $$A = \sum_{k=1}^n \frac{\pi r^2}{ n} = \pi r^2.$$ Rewriting this in terms of $\theta = 2 \pi/n$, we get that $$A =\sum_{k=1}^{\frac{2\pi}{\theta}} \theta \frac{r^2}{2}.$$ Now by taking the limit $n \to \infty$ $(\theta \to 0)$, we get $$\int_0^{2\pi}\frac{r^2}{2}d\theta.$$ The story does not change much if $r$ depends on $\theta$, or if $\theta_0$ and $\theta_1$ are different. The idea remains that you are summing an infinite amount of infinitesimally small circle sector areas.